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=5Y^2-60Y+16
We move all terms to the left:
-(5Y^2-60Y+16)=0
We get rid of parentheses
-5Y^2+60Y-16=0
a = -5; b = 60; c = -16;
Δ = b2-4ac
Δ = 602-4·(-5)·(-16)
Δ = 3280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3280}=\sqrt{16*205}=\sqrt{16}*\sqrt{205}=4\sqrt{205}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{205}}{2*-5}=\frac{-60-4\sqrt{205}}{-10} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{205}}{2*-5}=\frac{-60+4\sqrt{205}}{-10} $
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